(3c+6)(3c-6)=3c^2-6^2

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Solution for (3c+6)(3c-6)=3c^2-6^2 equation: 



(3c+6)(3c-6)=3c^2-6^2

We move all terms to the left:

(3c+6)(3c-6)-(3c^2-6^2)=0

We use the square of the difference formula

9c^2-(3c^2-6^2)-36=0

We get rid of parentheses

9c^2-3c^2-36+6^2=0

We add all the numbers together, and all the variables

6c^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{12}=0$

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